# During an experiment a scientist poured a 0.256-liter solution into a beaker. Four- hundredths of the solution was alcohol. How many liters of the solution was alcohol?

A 4% $\left(\frac{v}{v}\right)$ solution of alcohol in water is nominally $4$ $m L$ alcohol in $96$ $m L$ of water.
So if it's a $\text{4%}$ solution, $\text{volume of alcohol}$ $=$ 4%xx0.256*L $\cong$ $10 \cdot m L$.