Question

Dy/dx = y - 2x how to implicity differentiate?

Answer 1

`(d^2y)/(dx^2} = y-2x - 2`

Explanation:

We have:

`dy/dx = y-2x` ..... [A]

If we wish to implicitly differentiate this equation, then it is assumed that the second derivative is sought, so differentiating [A] wrt `x` we get:

`d/dx{dy/dx} = d/dx{y} - d/dx{2x}`

`:. (d^2y)/(dx^2} = dy/dx - 2`

`\ \ \ \ \ \ \ \ \ \ \ \ = y-2x - 2`