Eight electric dipoles (each having charge 'e') are placed at the centre of a regular cube of each side '1m'. What is the total normally outward flux through the cube?
1 Answer
Jun 11, 2018
See below
Explanation:
Each dipoles has net charge of zero. Gauss Law states that:
- The total of the electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity.
ie:
#Phi = Q_("enc")/varepsilon_o = 0#
The words "total normally outward flux " are confusing
Confusing because:
-
the flux through the cube's surface should be zero as explained
-
in EM certainly, flux is a scalar. It does not have a direction vector, so the idea that it could be normal to anything makes no sense.
