Electric charge?

Q1.) An electron (of mass #9.11*10^-31kg# and charge #-1.6*10^-19C#) in an old television is accelerated from rest through a voltage of #11000V#.
How much work is done on the charge ?

Q2.) What is its final speed?

1 Answer
Jane
Mar 11, 2018

Work done #W# realted to move a charge of #Q# through potential difference of #V# is, #W=VQ#

Given, #Q=-1.6*10^-19,V=11000V#

So, #W=-17.6*10^-16J#

Here,negative work done means the electron flows against the direction of electric field due to attractive force,so work is done by the electrostatic force.

So,we can say this much work will get stored as kinetic energy within it. So at this moment if its velocity is #v#,then.

#1/2 mv^2=W#

Given, #m=9.11*10^-(31)Kg#

So,we get, #v=6.205*10^7 ms^-1#

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