# Estimate the number of moles of solute present in each of the following solutions 256 mL of 0.358 M Ca(NO3)2 and 4 liters of 0.516 M HBr??

Jul 31, 2017

By definition, $\text{concentration"="moles of solute"/"volume of solution}$

#### Explanation:

And thus $\text{moles of solute}$ is given by the product $\text{volume"xx"concentration}$......

For the $C a {\left(N {O}_{3}\right)}_{2} \left(a q\right)$ solution, we has........

$256 \cdot m L \times {10}^{-} 3 \cdot L \cdot m {L}^{-} 1 \times 0.358 \cdot m o l \cdot {L}^{-} 1 = 0.0917 \cdot m o l$ WITH RESPECT TO $\text{calcium nitrate}$

And for the $H B r \left(a q\right)$ solution, we has........

$4.00 \cdot L \times 0.516 \cdot m o l \cdot {L}^{-} 1 = 2.064 \cdot m o l$ WITH RESPECT TO $\text{hydrobromic acid}$......