Question

Estimate the number of moles of solute present in each of the following solutions 256 mL of 0.358 M Ca(NO3)2 and 4 liters of 0.516 M HBr??

Answer 1

By definition, `"concentration"="moles of solute"/"volume of solution"`

Explanation:

And thus `"moles of solute"` is given by the product `"volume"xx"concentration"`......

For the `Ca(NO_3)_2(aq)` solution, we has........

`256*mLxx10^-3*L*mL^-1xx0.358*mol*L^-1=0.0917*mol` WITH RESPECT TO `"calcium nitrate"`

And for the `HBr(aq)` solution, we has........

`4.00*Lxx0.516*mol*L^-1=2.064*mol` WITH RESPECT TO `"hydrobromic acid"`......