# Evaluate (d/dx)(e^((3x^2)+3x))?

Jan 23, 2018

$\frac{d}{\mathrm{dx}} \left[{e}^{3 {x}^{2} + 3 x}\right] = {e}^{3 {x}^{2} + 3 x} \left(6 x + 3\right)$

#### Explanation:

Did you mean d/dx[e^(3x^2+3x)]? and by evaluate you mean differentiate?

If so, we'll use the chain rule:

$\frac{d}{\mathrm{dx}} \left[{e}^{3 {x}^{2} + 3 x}\right] = {e}^{3 {x}^{2} + 3 x} \cdot \frac{d}{\mathrm{dx}} \left[3 {x}^{2} + 3 x\right]$

$\frac{d}{\mathrm{dx}} \left[{e}^{3 {x}^{2} + 3 x}\right] = {e}^{3 {x}^{2} + 3 x} \cdot \left(6 x + 3\right)$