Evaluate #int_0^1x^2dx# ignore limits on the integral ?

1 Answer
Apr 7, 2018

#intx^2dx=x^3/3+C#

Explanation:

If you're ignoring the limits and looking for the indefinite integral, recall that

#intx^adx=x^(a+1)/(a+1)+C, a ne -1, C# represents the constant of integration

Here, #a=2 ne -1#, so

#intx^2dx=x^(2+1)/(2+1)+C=x^3/3+C#