Evaluate the definite integral.?

enter image source here

1 Answer
Andrea S.
Nov 16, 2017

#int_0^(root(5)(pi)) x^4cos(x^5)dx = 0#

Explanation:

#int_0^(root(5)(pi)) x^4cos(x^5)dx = 1/5 int_0^(root(5)(pi)) cos(x^5)d(x^5)#

#int_0^(root(5)(pi)) x^4cos(x^5)dx = 1/5 [sin(x^5)]_0^(root(5)(pi))#

#int_0^(root(5)(pi)) x^4cos(x^5)dx = 1/5 (sin ( (root(5)(pi))^5) -sin(0))#

#int_0^(root(5)(pi)) x^4cos(x^5)dx = 1/5 (sin ( pi) -sin(0)) = 0#

Related questions
Impact of this question
368 views around the world
You can reuse this answer
Creative Commons License