Some possible questions:

**1. What are the #x# and #y# intercepts for this equation?**

a) The #y# intercept is the value of the equation when #x=0#

In this case if #x=0#

#color(white)("XXX")F(0)=0^2+6xx0+8=8#

So the #y# intercept is #8#

b) The #x# intercepts are the values of #x# for which the equation is equal to #0#

In this case if #x^2+6x+8=0#

#color(white)("XXX")#We can factor the expression on the left:

#color(white)("XXX")(x+2)(x+4)=0#

#color(white)("XXX")rarr{:((x+2)=0,color(white)("xx")"or"color(white)("xx"),(x+4)=0),
(rarr x=-2,,rarr x=-4)
:}#

So the #x# intercepts are #(-2)# and #(-4)#

**2. What is the vertex of this equation?**

We can convert this equation into vertex form: #F(x)=(x-color(red)a)^2+color(blue)b# with vertex at #(color(red)a,color(blue)b)#

#color(white)("XXX")F(x)#

#color(white)("XXXXX")=x^2+6x+8#

#color(white)("XXXXX")=x^2+6x+9-1#

#color(white)("XXXXX")=(x+3)^2-1#

#color(white)("XXXXX")=(x-color(red)((-3)))^2+color(blue)((-1))#

which is the vertex form with vertex at #(color(red)((-3)),color(blue)((-1)))#

**3. Draw the graph of this equation**

graph{x^2+6x+8 [-8.836, 2.266, -1.523, 4.024]}