#F(x)=x^6-x-1# cuts the #x# axis at how many points?

1 Answer
Jun 17, 2018

#2#

Explanation:

Given:

#F(x) = x^6-x-1#

The pattern of signs of the coefficients of #F(x)# is #+ - -#. With one change of signs, Descartes' Rule of Signs tells us that #F(x)# has exactly one positive real zero.

The pattern of signs of the coefficients of #F(-x)# is #+ + -#. With one change of signs, Descartes' Rule of Signs tells us that #F(x)# has exactly one negative real zero.

So #F(x)# intersects the #x# axis at two points - one negative and one positive.

graph{x^6-x-1 [-2.2, 2.2, -3.24, 6.76]}