Factor #27x^3y^3+8#?

1 Answer
Jim G.
May 26, 2017

#(3xy+2)(9x^2y^2-6xy+4)#

Explanation:

#27x^3y^3+8" is a "color(blue)"sum of cubes"" and in"#
#"general factorises as"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(a^3+b^3=(a+b)(a^2-ab+b^2))color(white)(2/2)|)))#

#27x^3y^3=(3xy)^3rArra=3xy#

#8=2^3rArrb=2#

#rArr27x^3y^3+8=(3xy+2)(9x^2y^2-6xy+4)#

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