Factorise #x²+7xy+12y²# ?

2 Answers
Apr 27, 2018

See the answer below...

Explanation:

#x^2+7xy+12y^2#

#=x^2+3xy+4xy+12y^2" "#

#=x(x+3y)+4y(x+3y)#

#=color(red)(ul(bar(|color(green)((x+3y)(x+4y))|#

[It is called middle term factor process of factorization.]

Here, you have to break the middle factor in such a way that the the product of the formers will be equal to the products of the co-efficient of the first and last term with sign.

Hope it helps...

Thank you...

:-)

Apr 27, 2018

#(x+3y)(x+4y)#

Explanation:

#"this can be factored in the same way as a quadratic"#
#"in one variable"#

#"the factors of + 12 which sum to + 7 are + 3 and + 4"#

#rArrx^2+7xy+12y^2=(x+3y)(x+4y)#