Question

Factorize Please?? 5(3x+y)^2+6(3x+y)-8

Answer 1

`(15x+5y-4)(3x+y-2)=0`

Explanation:

`5(3x+y)^2+6(3x+y)-8=0`

First, you let `3x+y` be just a pronumeral. I'm going to let it equal to a.

`5a^2+6a-8=0`

Solve normally as you would with a quadratic equation. You can use either the quadratic formula or the "criss-cross" method.
`(5a-4)(a+2)=0`

Now, subbing `a=3x+y` back into the equation gives:

`(5(3x+y)-4)(3x+y+2)=0`
`(15x+5y-4)(3x+y-2)=0`