# Find 2 coordinates of the points where the function has a horizontal tangent line? 2y^2+4x^2-y=16x

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Shwetank Mauria
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Feb 9, 2018

#### Answer:

Tangent is horizontal at

#### Explanation:

The function

Hence let us first find the derivative of

or

or

and this is zero when

When

or

or

i.e.

i.e.

Hence tangent is horizontal at

graph{(2y^2+4x^2-y-16x)((x-2)^2+(y-3.09)^2-0.02)((x-2)^2+(y+2.59)^2-0.02)=0 [-10, 10, -5, 5]}

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