Find all the solutions to the equation in the interval 0,2pi? Sin(x+pi/2)-cos^2x=0
1 Answer
Feb 13, 2018
Explanation:
Use
#sinxcos(pi/2) + sin(pi/2)cosx - cos^2x = 0#
#sinx(0) + cosx - cos^2x= 0 #
#-cosx(cosx - 1) = 0#
#cosx = 0 or cosx = 1#
#x= pi/2, (3pi)/2 or 0#
Hopefully this helps!