Find an equation in standard form of the line through (-1,3) and parallel to the line containing (1,5) and (3,0)?

1 Answer
Jun 20, 2018

#5x+2y=1#

Explanation:

#"the equation of a line in "color(blue)"standard form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))#

#"where A is a positive integer and B, C are integers"#

#"to begin obtain the equation in "color(blue)"point-slope form"#

#•color(white)(x)y-b=m(x-a)#

#"where m is the slope and "(a,b)" a point on the line"#

#"to calculate m use the "color(blue)"gradient formula"#

#•color(white)(x)m=(y_2-y_1)/(x_2-x_1)#

#"let "(x_1,y_1)=(1,5)" and "(x_2,y_2)=(3,0)#

#m=(0-5)/(3-1)=(-5)/2=-5/2#

#• " Parallel lines have equal slopes"#

#"using "m=-5/2" and "(a,b)=(-1,3)#

#y-3=-5/2(x+1)larrcolor(red)"in point-slope form"#

#"distribute and rearrange for standard form"#

#y-3=-5/2x-5/2#

#y=-5/2x+1/2#

#"multiply all terms by 2"#

#2y=-5x+1#

#5x+2y=1larrcolor(red)"in standard form"#