Find an expression for the power series, then use the ratio test to find the radius of convergence?

#1+2x+(4x^2)/(2!)+ (8x^3)/(3!)+(16x^4)/(4!)+(32x^5)/(5!)+cdots#

1 Answer
Apr 5, 2018

Notice the numerators are the powers of #2# starting at #0#. Therefore,

#sum_(n = 0)^oo (2x)^n/(n!)#

The radius of convergence is given by the ratio test:

#L = lim_(n ->oo) ((2x)^(n + 1)/((n + 1)!))/(((2x)^n)/(n!))#

#L = lim_(n -> oo) (2x)/(n + 1)#

#L = 2|x| lim_(n->oo) 1/(n + 1)#

#L = 0#

This means that the sequence converges for all values of #x#.

Hopefully this helps!