Find g’(9) where g(x)=(squareroot(x)+3)/(squareroot(x)-1) ?

1 Answer
Feb 16, 2018

3

Explanation:

#g(x)=(sqrtx+3)/(sqrtx -1)#

Now substitute #color(red)(9)# for every time you see #color(red)x# in the expression:

#g(color(red)9) = (sqrtcolor(red)9+3)/(sqrtcolor(red)9 -1)#

and simplify:

#g(9)=(3+3)/(3-1)#

#g(9)=6/2#

#g(9)=3#