Find no of molecules of S4 of 16g of sulphur powder? (S=32u)

1 Answer
Feb 18, 2018

I don't think #S_4# exists. So, if the sulfur powder has a chemical formula of just #S#, then there would be #3.01*10^23# molecules of #S#.

Explanation:

We know that #S# has a molar mass of #32 \ "g/mol"#.

So, in #16 \ "g"# of #S#, there would exist

#(16 \ cancel"g")/(32 \ cancel"g""/mol")=0.5 \ "mol of" \ S#

We also know that

#1 \ "mol"=N_A~~6.02*10^23#

So, #0.5 \ "mol"=6.02*10^23*0.5=3.01*10^23#

Therefore, there would be #3.01*10^23# atoms of sulfur in #16 \ "g"# of pure sulfur powder.