Find the absolute value of 2 sqrt3 - 2i ?

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Answer 1 · 2018-05-19T18:29:43

#4#

#abs(a + bi) = sqrt(a^2 + b^2)#

#abs(2 sqrt3 - 2i)#

#a = 2sqrt3#

#b = -2#

#sqrt((2sqrt3)^2 +(-2)^2)#

#sqrt((4*3) +(4))#

#sqrt(12 +4)#

#sqrt(16)#

#4#