Find the area of triangle ABC and round to the nearest tenth:b=16, c=8, angle B= 100 ?

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Answer 1 · 2018-02-27T08:01:36

Area of #Delta # ABC #A_t = (1/2) b c sin A = (1/2) * 16 * 8 * sin 50.5 #

#=> 49.4# sq units (rounded to one decimal).

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#b = 16, hatB = 100^@, c = 8#

#sin C = (c * sin B) / b = (8 * sin 100) / 16 = 0.4924#

#hatC = sin_-1 0.4924 = 29.49^@#

#hat A = 180 - 100 - 29.5 = 50.5^@#

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Known two sides and included angle

Area of #Delta ABC #A_t = (1/2) b c sin A = (1/2) * 16 * 8 * sin 50.5 = 49.4# sq units (rounded to one decimal).