Find the center and radius of x^2+y^2+6y-8x=0?

1 Answer
May 1, 2018

centre is #(4,-3)#

radius is # 5#

Explanation:

Rearrange #=> x^2-8x+y^2+6y=0#

Complete the square

#=> (x-4)^2-16+(y+3)^2-9=0#

Put into the general equation format

#=> (x-4)^2+(y+3)^2=25#

so the centre is #(4,-3)# and the radius is# sqrt25=5#