Find the derivative of x+cosx÷tanx with respect to x?

1 Answer
Write your answer here...
Start with a one sentence answer
Then teach the underlying concepts
Don't copy without citing sources
preview
?

Answer

Write a one sentence answer...

Answer:

Explanation

Explain in detail...

Explanation:

I want someone to double check my answer

Describe your changes (optional) 200

5
Feb 25, 2017

Answer:

# d/dx (x+cosx ÷ tanx ) = 1 - cosx - cotxcscx #

Explanation:

# d/dx (x+cosx ÷ tanx ) = d/dx (x+cosx/tanx ) #
# " "= d/dx (x)+d/dx(cosx/tanx) #
# " "= 1 + { (tanx)(-sinx) - (cosx)(sec^2x) }/ (tanx)^2 #
# " "= 1 - (tanx)(sinx)/tan^2x - (cosx)(sec^2x)/(tanx)^2 #
# " "= 1 - (sinx)*cosx/sinx - (cosx)(1/cos^2x)*cos^2x/sin^2x #

# " "= 1 - cosx - (cosx)/sin^2x #

# " "= 1 - cosx - cotxcscx #

Was this helpful? Let the contributor know!
1500