Find the equation of a parabola that has a vertex of (4,5) and contains the point (-2,-2)?

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Answer 1 · 2018-03-06T05:27:07

# 36(y-5)=-7(x-4)^2#

We know that, the eqn. of a parabbola #S# having its vertex at

#(h,k)# is given by,

# S : (y-k)=a(x-h)^2#.

So, in our case, # S : (y-5)=a(x-4)^2#.

To determine the constant #a#, we use the given condition that,

#(-2,-2) in S#.

#;. (-2-5)=a(-2-4)^2, or, a=-7/36#.

# rArr S : 36(y-5)=-7(x-4)^2#, is the desired eqn.