Find the equation of tangent at point where the curve y=2e^(-x/3) cuts Y-axis?
1 Answer
Mar 7, 2018
Explanation:
#•color(white)(x)m_(color(red)"tangent")=dy/dx" at x = a"#
#y=2e^((-x/3))#
#rArrdy/dx=2e^((-x/3))xxd/dx(-1/3x)larrcolor(blue)"chain rule"#
#color(white)(rArrdy/dx)=-2/3e^((-x/3))#
#"crosses y-axis when "x=0#
#x=0toy=2e^0=2rArr(0,2)#
#m_(color(red)"tangent")=-2/3e^0=-2/3#
#rArry-2=-2/3x#
#rArry=-2/3x+2larrcolor(red)"equation of tangent"#
