Find the equation of the plane passing through (2,3,-1) and perpendicular to the line joining the points (3,4,-1) and (2,-1,5) ?

1 Answer
Apr 14, 2018

#5y+14x-27.2=0#

Explanation:

I'm assuming the points are (3.4,-1), (2,-1.5) and (2.3,-1)

gradient= #(-1+1.5)/(3.4-2)# = #5/14#

Since the line is perpendicular, then its gradient is equal to #-1/(5/14)# = #-14/5#

Using point gradient form,

#(y+1)=-14/5(x-2.3)#

#5y+5=-14x+32.2#

#5y+14x-27.2=0#