Find the indefinite integral?

Find the indefinite integral without using the substitution method.

#int2^x(3^x+5^x)#

1 Answer
Nov 20, 2017

#int 2^x(3^x+5^x) dx = 6^x/ln 6+10^x/ln 10 + C#

Explanation:

Note that in general:

#d/(dx) a^x = d/(dx) e^(x ln a) = (ln a) e^(x ln a) = (ln a) a^x#

So:

#int a^x dx = a^x/(ln a) + C#

So we find:

#int 2^x(3^x+5^x) dx = int 6^x+10^x dx#

#color(white)(int 2^x(3^x+5^x) dx) = 6^x/ln 6+10^x/ln 10 + C#