Find the limit? lim x#rarr# #oo# #(10x^5+x^4+31)/(x^6)#

2 Answers
Rhys
Oct 29, 2017

#0#

Explanation:

Hence # (10x^5+x^4+31)/x^6# can be written as;

#(10+1/x+31/x^5) / x #

Hence as # x -> oo#,#1/x->0 and 31/x^5->0#

Hence the limit becomes;

#lim_(x->oo) 10/x #

and we know as #x -> oo#, #10/x ->0#

Hence yielding an answer of 0

Jim G.
Oct 29, 2017

#0#

Explanation:

#"divide terms on numerator by "x^6#

#rArr(10x^5)/(x^6)+(x^4)/(x^6)+31/(x^6)=10/x+1/x^2+31/x^6#

#rArrlim_(xtooo)(10x^5+x^4+31)/(x^6)#

#=lim_(xtooo)10/x+1/x^2+31/x^6=0#

Related questions
Impact of this question
870 views around the world
You can reuse this answer
Creative Commons License