Find the most general antiderivative of f(x)=2^(x+1)?

1 Answer
Nov 20, 2017

The most general antiderivative of #2^(x+1)# is #2^(x+1)/ln2#+C

Explanation:

The derivative of #2^(x+1)# is #2^(x+1) ln2#.

So, to find the antiderivative of #2^(x+1)# we need to get rid of the factor of #ln2#

The derivative of #2^(x+1)/ln2# is #2^(x+1)#.

So the most general antiderivative of #2^(x+1)# is #2^(x+1)/ln2#+C