Find the number of terms (geometric progressions) in 6,18,54,...,1458 ?

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Answer 1 · 2017-10-31T08:40:45

#6#

#6,18,54,...1458#

the common ratio

#r=18/6=3#

the nth term is given by

#nth=ar^(n-1)#

#:.1458=6*3^(n-1)#

#1458/6=3^(n-1)#

#243=3^(n-1)#

#because 3^5=243#

#n-1=5#

#n=6#