Find the pH of the solution formed when 0.02 mol of HCL is added to enough water to make the final volume 2.0 L ?

1 Answer
anor277
Apr 28, 2018

Well, what is #pH#, and what is concentration of #HCl#? We get #pH=2#...

Explanation:

In reverse order we may find the concentration of #HCl(aq)# by taking the quotient...

#"Concentration"="Moles of solute"/"Volume of solution"=(0.02*mol)/(2.0*L)#

#[HCl]=0.010*mol^-1=1.0xx10^-2*mol*L^-1#...

But #pH=-log_10[H_3O^+]=-log_10(10^-2)=--2=+2#

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