Find the remainder when #9 xx 99 xx 999 xx \underbrace{99 cdots 9}_{2017" " 9's}# is divided by #1000#?
1 Answer
Sep 12, 2017
Explanation:
Modulo
#9*99*999*overbrace(99...9)^"2017 9's" -= 9*99*(-1)*(-1) -= 891#
