# Find the slope of the line containing the following two points? (7/6,-5) and (-1/3,-1/3)

Apr 25, 2018

The slope is $- 3 \frac{1}{9}$.

#### Explanation:

Use the slope formula:

(y_2-y_1)/(x_2 - x_1) = m" " ["slope"]

Here

• $\left(\frac{7}{6} , - 5\right) = \left({x}_{1} , {y}_{1}\right)$
• $\left(- \frac{1}{3} , - \frac{1}{3}\right) = \left({x}_{2} , {y}_{2}\right)$

So

$- \frac{1}{3} - \left(- 5\right)$

becomes

$- \frac{1}{3} + 5$

because two negatives create a positive.

$m = \frac{- \frac{1}{3} + 5}{\left(- \frac{1}{3}\right) - \frac{7}{6}}$

$m = - 3.1111 = - 3 \frac{1}{9}$

Apr 25, 2018

$\text{slope} = - \frac{28}{9}$

#### Explanation:

$\text{slope} = \frac{{y}_{2} - {y}_{1}}{{x}_{2} - {x}_{1}}$

So

$\text{slope} = \frac{- \frac{1}{3} - \left(- 5\right)}{- \frac{1}{3} - \frac{7}{6}}$

$\text{slope} = - \frac{28}{9}$