# Find the solution of the differential equation #xy'=y+x^2\sinx# that satisfies the given initial conditions below?

##
#y(\pi)=0#

I know it's in #dy/dx+P(x)y=Q(x)# form, but what exactly is the integrating factor?

Like what is "exp" in #I=exp(\int P(x)dx)# ?

(People use this a lot when mentioning the integrating factor, but I learned it as #I(x)=e^(\intP(x)dx)# ...)

I know it's in

Like what is "exp" in

(People use this a lot when mentioning the integrating factor, but I learned it as

##### 1 Answer

Apr 25, 2018

Refer to the **Explanation.**

#### Explanation:

**exponential function.**

So, **another way** to denote

I hope I've cleared your doubt!

By the way, I presume that you know how to solve the given diff.

eqn., so, I don't solve it!