Find the value of ?

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1 Answer
Ratnaker Mehta
Sep 12, 2017

# theta=pi/3.# In general, #theta=-2npi+2pi/3, n in ZZ.#

Explanation:

#tan(pi/2-theta/2)=sqrt3=tan(pi/3).#

#:. -theta/2=pi/3-pi/2=-pi/6.#

#:. theta=pi/3.#

In General, since, #tanx=tany rArr x=npi+y, n in ZZ,# we have,

#pi/2-theta/2=npi+pi/3 rArr theta=-2npi+pi/3, n in ZZ.#

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