Find the value of the surface integral (2x^2yi - y^2j + 4xz^2k).dS where is S the surface of the cylinder y^2 + z^2 = 9 bounded by the planes x=0 and x=2?

1 Answer
May 4, 2018

See below

Explanation:

#int int_S ((2x^2y),( - y^2), (4xz^2)) * d bb S#

By the divergence theorem, flux for the entire surface is:

#= int int int_V \ 4xy - 2y + 8xz \ dV#

#= int_(x = 0)^2 dx\ int_(y = -3)^3 dy \ int_(z = - sqrt(9 - y^2))^( sqrt(9 - y^2)) dz qquad \ 2y(2x - 1) + 8xz #

#= int_(x = 0)^2 dx\ int_(y = -3)^3 dy \ qquad \ [2yz(2x - 1) + 4xz^2]_(- sqrt(9 - y^2))^( sqrt(9 - y^2)) #

#= int_(x = 0)^2 dx\ int_(y = -3)^3 dy \ qquad \ 4ysqrt(9 - y^2)(2x - 1) #

#= int_(x = 0)^2 dx\ qquad [ \ - 4/3 sqrt(9 - y^2)^(3/2)(2x - 1) ]_(y = -3)^3 = 0 #

That's the flux across the entire cylinder surface, including the end caps.

If they are meant to be excluded, then:

  • End cap at #x = 0#, #bb hat n = langle -1 , 0 , 0 rangle#:

#int int_S ((2x^2y),( - y^2), (4xz^2)) * d bb S#

#= int int_S ((0),( - y^2), (0)) * ((-1),(0),(0)) \ dy \ dz = 0#

  • End cap at #x = 2#, #bb hat n = langle 1 , 0 , 0 rangle#:

#int int_S ((2x^2y),( - y^2), (4xz^2)) * d bb S#

#= int int_S ((8y),( - y^2), (8z^2)) * ((1),(0),(0)) \ dy \ dz#

#= 8 int_0^3 \ dz int_(- sqrt(9 - z^2))^( sqrt(9 - z^2)) \ dy \ qquad y = 0#