Find the value of "x" that satisfies the equation : √3 sin 2x + cos 2x = √3 ; 0°<= x <= 90° ?

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Answer 1 · 2017-10-13T03:32:16

#√3 sin 2x + cos 2x = √3 #

#=>sqrt3/2 *sin 2x + 1/2*cos 2x = sqrt3/2 #

#=>cos(30^@) *sin 2x + sin(30^@)*cos 2x = sin(60^@)=sin(120^@) #

#=>sin(2x+30^@)=sin(60^@)=sin(120^@) #

#=>2x+30=60^#

#=>x=15^@#

Again

#=>2x+30=120^@#

#=>x=45^@#