# Flexible plastic container with 0.86 g of 19.2 L helium gas. If you remove 0.205 grams of helium gas in continuous pressure and temperature, what is the new size?

##### 2 Answers

I got

#### Explanation:

This is a case of Avogadro's law, that is

We first need to convert

So,

Now, if we remove

the new amount becomes

Plugging in the values, we get

14.62 liters

#### Explanation:

The requested answer was the new size reached by the flexible container (presumably a balloon)

Removing 0.205 grams of helium brings the mass to 0.655 grams.

By a simple proportion:

0.86 g : 0.655 g = 19.2 L : x L

x= 14.62

The new size of the container is 14.62 L

No need to calculate moles number.

The above calculation holds true for every gas