For a school play, one adult ticket cost $5 and one student ticket cost $3. Twice as many student tickets as adult tickets were sold. The total receipts were $1650. How many of each kind of ticket were sold?
As the number of student tickets sold is twice the number of adult tickets, there is only one solution,
150 adult tickets and 300 student tickets.
The total was $1650
Let N be the number of adult tickets sold..
Then, the number of student tickets sold is 2N
So, N(5$) + 2N(3$ )= 1650$.
11N$ = 1650$.
N = 150.
Of course, (175, 275) is also a positive-integer solution that does not satisfy the given condition that the second number is twice the first.