# For the curve y=x-x^2, how do you find the slope of the tangent line to the curve at (1,0)?

##### 1 Answer
Apr 27, 2015

First you evaluate the derivative of your function $y ' \left(x\right)$:
Then you evaluate the derivative at $x = 1$, or $y ' \left(1\right)$, which is the slope of your tangent line.
Try by yourself and if it doesn' work look below for the maths:
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Solution:
$y ' \left(x\right) = 1 - 2 x$
$y ' \left(1\right) = 1 - 2 = - 1$