For the rate law expression rate=k[A][B]^2, what happens to the rate if the concentration of B is increased by a factor of two ?
1 Answer
May 16, 2018
Let's find out...
Given the rate law
#r_1(t) = k[A][B]^2# ,
doubling the concentration of
#r_2(t) = k[A] (2[B])^2#
#= 4 cdot k[A][B]^2#
And since
#r_2(t) = 4 cdot r_1(t)#
Thus, the rate quadruples. What is the order with respect to reactant
