For the reaction #2H_2 + O_2 -> 2H_2O#, how many moles of water can be produced from 6.0 mol of oxygen?
As you know, the stoichiometric coefficients attributed to each compound in the balanced chemical equation can be thought of as moles of reactants needed or moles of products formed in the reaction.
In your case, the balanced chemical equation for this synthesis reaction looks like this
#2"H"_text(2(g]) + "O"_text(2(g]) -> color(red)(2)"H"_2"O"_text((l]])#
Notice that the reaction requires
This tells you that the reaction produces twice as many moles of water as you have moles of oxygen gas that take part in the reaction.
You know that your reaction uses
#6.0 color(red)(cancel(color(black)("moles O"_2))) * (color(red)(2)" moles H"_2"O")/(1color(red)(cancel(color(black)("moles O"_2)))) = color(green)("12 moles H"_2"O")#