# For the reaction C+2H_2 -> CH_4, how many grams of hydrogen are required to produce 0.6 moles of methane, CH_4?

Mar 14, 2016

$2.40$ grams ${H}_{2}$

#### Explanation:

1. Start by determining the mole ratio of $C {H}_{4}$ and ${H}_{2}$; it can be on these form and use the appropriate ratio depending on your desired unit;
$\frac{1 m o l C {H}_{4}}{2 m o l {H}_{2}}$
or
$\frac{2 m o l {H}_{2}}{1 m o l C {H}_{4}}$
2. Once known, multiply the value to the mole of $C {H}_{4}$ as provided in the problem to find the mole of ${H}_{2}$;
0.6 mol $C {H}_{4}$ x ?
3. Then, find the molar mass of ${H}_{2}$ to use to find the mass of ${H}_{2}$ needed to produce $C {H}_{4}$.
4. The answer is $2.4$ grams of ${H}_{2}$