# For what values of x, if any, does f(x) = 1/((x+8)(x-7))  have vertical asymptotes?

##### 1 Answer
Jan 9, 2016

Vertical asymptotes: $x = - 8$ and $x = 7$

#### Explanation:

$f \left(x\right) = \frac{1}{\left(x + 8\right) \left(x - 7\right)}$

The vertical asymptotes are found when the denominator of the function becomes zero.

To find the Vertical asymptote we equate the denominator to zero.

$\left(x + 8\right) \left(x - 7\right) = 0$

Using zero product rule we get

$x + 8 = 0$ or $x - 7 = 0$

$\implies x = - 8$ or $x = 7$

Vertical asymptotes: $x = - 8$ and $x = 7$