Gas mass 41.2cm3 in temperature 45C calculate the same volume in temperature 20C in the pressure is constant?

1 Answer
anor277
Feb 18, 2018

Well, we use old #"Charles' Law"#

Explanation:

...the which holds that #VpropT# give constant pressure, and a constant quantity of gas....the which scenario applies here..

And so if #VpropT#...then #V=kT#...and if we solve for #k#, the so-called #"constant of proportionality..."#

#k=V/T#...but given the boundary limits this should be true for all values of volume and temperature....and so...

#V_1/T_1=V_2/T_2#...and as usual we use units of #"absolute temperature.."#

And so (finally!), #V_2=V_1/T_1xxT_2#

#(41.2*cm^3)/(318.15*K)xx293.15*K=35.4*cm^3#...

...the volume has reduced slightly, as we would anticipate at lower temperature. Note that for this experiment to work the gas must have been enclosed in a piston, which could expand or contract against atmospheric temperature. Do you follow?

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