Given #a:b:c=11:5:3# and #b-c=12#. What is the value of #a+b+c#?

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Answer 1 · 2017-11-27T21:14:36

#a+b+c = 114#

Given the ratio of #b:c = 5:3# we can write the following equation:

#5/3=b/c#

Solve for c:

#c=3/5b#

Substitute this into the given equation #b-c = 12#

#b - 3/5b = 12#

#2/5b = 12#

#b = 30#

Use the equation #c = 3/5b# to find the value of c:

#c = 3/5(30)#

#c = 18#

Given the ration of #a:b= 11:5#, we can write the following equation:

#11/5= a/b#

#a = 11/5(30)#

#a = 66#

#a+b+c = 66+30+18#

#a+b+c = 114#