Given f(x) = x +2 and g(x)= 2x^2-4x+2, how do you find f(x) ÷ g(x)?

$\frac{1}{2} \frac{x + 2}{x - 1} ^ 2$
$f \frac{x}{g} \left(x\right) = \frac{x + 2}{2 {x}^{2} - 4 x + 2}$
$\Rightarrow \frac{x + 2}{2 \left\{{x}^{2} - 2 x + 1\right\}}$
$\Rightarrow \frac{1}{2} \frac{x + 2}{x - 1} ^ 2$