Given #f(x) = (x^2 + x - 6)/ (x + 3)# how do you find the limit as x approaches -2?
1 Answer
Jul 29, 2016
-4
Explanation:
since neither the numerator nor denominator equal zero when x = -2, then the limit can be found by direct substitution.
#rArrlim_(xto-2)f(x)=((-2)^2-2-6)/(-2+3)=(-4)/1=-4#
