# Given h(x) = 5x^2 - 4x how do you find h(-3)?

It is $h \left(- 3\right) = 57$
Hence $h \left(x\right) = 5 {x}^{2} - 4 x$ then just replace $x$ for $- 3$
h(-3)=5*(-3)^2-4*(-3)=>h(-3)=45+12=> h(-3)=57