Question

Given `sin(-x)=-1/3, tanx=-sqrt2/4` to find the remaining trigonometric function?

Answer 1

`sin (-x) = - 1/3 = - sin x` --> `sin x = 1/3`
`cos x = tan x/(sin x) = (-sqrt2/4)(3/1) = - (3sqrt2)/4`
`cot x = - 4/sqrt2 = - (4sqrt2)/2 = - 2sqrt2`
`sec x = 1/(cos) = - 4/(3sqrt2) = - (4sqrt2)/6 = - (2sqrt2)/3`
`csc x = 1/(sin) = 3`